Author Topic: Algebra 2 problem  (Read 1170 times)

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Offline RickyMcGee

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Algebra 2 problem
« on: October 06, 2014, 07:21:54 pm »
I got three similar math problems. I dont understand them.
1/8th under square root cubed
-125 under square root cubed
81 under square root cubed
Sorry that description stinks, but idk how else to describe it.
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Offline MessedThoughts

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Re: Algebra 2 problem
« Reply #1 on: October 06, 2014, 07:40:47 pm »
Sorry, im confused, what are you trying to do with these numbers (what are you trying to solve here in what terms)?

Also, i'm assuming that you mean cbrt(1/8), cbrt(-125) and cbrt(81)correct?
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Offline Essie

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Re: Algebra 2 problem
« Reply #2 on: October 06, 2014, 08:18:55 pm »
All they are asking you to do is simply by finding the cube roots
I can give you the answers, but first you need to understand cube roots.
An example of a cube is 81, and the cube root of 81 is 9, because 9x9x9=81. Do you see the relationship?
let's look at the cube root of -125, what number multiplied three times gives us -125?

The answer is -5, because -5x-5= positive 25, and then 25x-5= -125. Make sense?
Now you try to find the cube root of 1/8 and I'll tell you if it's right.
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Offline RickyMcGee

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Re: Algebra 2 problem
« Reply #3 on: October 06, 2014, 08:49:31 pm »
OK ok, I described the problem wrong. Its asking when cubed what number equals x
So when cubed what number equals 81
Sorry, the way they showed the problem was new to me, the little 3 is on the left side of the square root symbol. But still idk how to sovle it.
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Offline Essie

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Re: Algebra 2 problem
« Reply #4 on: October 06, 2014, 09:03:15 pm »
OK ok, I described the problem wrong. Its asking when cubed what number equals x
So when cubed what number equals 81
Sorry, the way they showed the problem was new to me, the little 3 is on the left side of the square root symbol. But still idk how to sovle it.
My bad, 81 is not a perfect cube. sorry i had a brainfart. You'll need a calculator to estimate that.
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Offline Mystic

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Re: Algebra 2 problem
« Reply #5 on: October 06, 2014, 09:10:54 pm »
If the little three is in the left side of the square root symbol then it's a cubed root, which as Sarka explained is basically what number multiplied by itself 3 times give you the number under the sign. So for the cubed root of 81, what number multiplied by itself 3 times gives you 81? And that is your cubed root. Same thing for the cubed root of -125. For the cubed root of 1/8 don't forget that the cubed root (or any root) of a fraction is the same as the root of the numerator over the root of the denominator. So the square root of 9/25 it the same as the square root of 9 over the square root of 25. For the cubed root of 1/8 it would be the same as the cubed root of 1 over the cubed root of 8

Hope this helps a bit, I'm not the best at explaining math through text so I hope this makes sense
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Offline NightF0x

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Re: Algebra 2 problem
« Reply #6 on: October 06, 2014, 09:12:06 pm »
https://www.youtube.com/watch?v=DKh16Th8x6o

Khan Academy is an excellent resource for math stuff.
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Offline RickyMcGee

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Re: Algebra 2 problem
« Reply #7 on: October 06, 2014, 10:10:20 pm »
OK, im getting how it works, so to find the number that you cube is it guess and check or is there a way to find it algebraically.
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Offline NightF0x

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Re: Algebra 2 problem
« Reply #8 on: October 06, 2014, 11:36:29 pm »
OK, im getting how it works, so to find the number that you cube is it guess and check or is there a way to find it algebraically.

Unfortunately cube roots are one of those things that is guess and check. It's dumb, but hold in there. Once you're out of Algebra 2 you won't have to do them by hand. It's just important to be able to understand how cube roots work. Everything you're doing now is building up for higher math classes. Your mind is going to melt when you get to Calculus, because you realize how useful math is.
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Offline Mystic

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Re: Algebra 2 problem
« Reply #9 on: October 07, 2014, 09:36:42 am »
OK, im getting how it works, so to find the number that you cube is it guess and check or is there a way to find it algebraically.

Unfortunately with roots it's really just a guess and check. Like with square roots you just know them, there's no equation to figure it out, its the same for all other types of roots. Just keep practicing and you'll start to memorize them like you have for square roots
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Offline Koala123

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Re: Algebra 2 problem
« Reply #10 on: October 07, 2014, 10:43:49 am »
I think there's an easier way.  I've been trying this for some time, and I think there's a pattern.
125, factorized equals 5x5x5.  So, the cube root of 125 is 5, right.?
81, factorized equals 9x9, which can be simplified into 3x3x3x3.  The cube root, joining 3 numbers together, is 3x(square root of 3), right?
I just think this is a simplier way to do it, but correct me if I'm wrong.
                   

Offline Mystic

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Re: Algebra 2 problem
« Reply #11 on: October 07, 2014, 10:59:20 am »
I think there's an easier way.  I've been trying this for some time, and I think there's a pattern.
125, factorized equals 5x5x5.  So, the cube root of 125 is 5, right.?
81, factorized equals 9x9, which can be simplified into 3x3x3x3.  The cube root, joining 3 numbers together, is 3x(square root of 3), right?
I just think this is a simplier way to do it, but correct me if I'm wrong.

It's a good idea but unfortunately doesn't work, 81 isn't a perfect cube (the cubed root of 81 is 4.326.....) and for a number like 64 (4 cubed) if you completely simplify it like that you get a bunch of two multiplying but the cubed root is 4. So unfortunately it doesn't work but was a really good idea :fox-:):
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Offline Koala123

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Re: Algebra 2 problem
« Reply #12 on: October 07, 2014, 11:20:41 am »
On, ok. I guess I'll learn this next year.
EDIT: I think I meant 3x(the CUBE root of 3) instead. :p
EDIT 2: Bored in yearbook class, let me think about your 64 example, Solstice.
If it's simplified all the way into 2x2x2x2x2x2, then the cube root would be 2x2, which would be easily simplified into 4.  I really don't see much error in my answer, but, of course, I could just be playing dumb. =p
« Last Edit: October 07, 2014, 02:35:37 pm by JustAnotherFursuiter »
                   

Offline RickyMcGee

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Re: Algebra 2 problem
« Reply #13 on: October 07, 2014, 05:52:32 pm »
Ok thanks guys, I understand it sooo much better now. Now to start this tedious work called guess and check.
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