If

**y = b**^{x},

then

**log**_{b}(y) = xWe would call this log base-b of y.

Lets say we have log

_{2}(x) = 3 and want to solve for x.

We can reorganize this into x = 2

^{3}Therefore x = 8

In the same way, log

_{2}(32) = x will yield:

2

^{x} = 32

Therefore x = 5

Compare the graph of these exponential and logarithmic functions.

Notice how they are reflections of each other across the line y = x.

In case you didn't already cover this, that means they're inverse functions.

Here are some rules to remember while dealing with logarithms:

Hope this helps!